ExamPlay Light Logo
Se connecter

JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 21)

In the figure given, the electric current flowing through the 5 k$$\Omega$$ resistor is 'x' mA.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English
The value of x to the nearest integer is ____________.
Répondre
3

Explication

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English Explanation
$$I = {{21} \over {5 + 1 + 1}}$$

$$ \therefore $$ I = 3 mA

Commentaires (0)

Connectez-vous pour commenter
Publicité
BrainBehindX Inc Logo
©2026; Alimenté par BrainBehindX Inc